本文共 453 字,大约阅读时间需要 1 分钟。
select
c.card_number,
c.card_name,
t.type_name,
c.card_discount,
t.type_low,
c.card_integral,
(c.card_recharge_balance+c.card_give_balance) as num,
v.people,
c.card_time
from
`vip_card` as c
left join
(
select
count(vipid) as people,
card_number
from vip
group by card_number
) as v
on
c.card_number=v.card_number
left join
`vip_type` as t
on
c.type_id=t.type_id
where
c.store_key='556655';
转载地址:http://uvvix.baihongyu.com/